Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Answer:
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Step-by-step explanation:
Answer: ≈ 185.73009
Step-by-step explanation:
area of square: 
area of circle: 
length: 15
radius = diameter/2
radius: 5
area of square - area of circle = area between square and circle:
≈ 185.73009
hope it helps!
Please mark as brainliest.
You can set up an equation based off of the information given:
x represents the unknown number
3/5x - 1 = 23
add 1 to both sides to isolate the 3/5x
3/5x = 24
divide both sides by 3/5 to solve for x
x = 120/3
120/3 can be simplified into 40
Final answer: x = 40
71/3=23.6
36/7=5.14
23.6-5.14=18.46
So, the correct answer is 18.46
