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3 years ago

Find the values of x, EF, and FG. The drawing is not to scale.

Mathematics

1 answer:

AVprozaik [17]3 years ago

6 0

Option D is the answer to your question!!!
Hope this helps you!!!

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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12 a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

2 years ago

What is the slope????

murzikaleks [220]

Answer:

-6

Step-by-step explanation:

is that quizzes join lol

8 0

3 years ago

Use substitution to solve each system of equations Y=2x-2 Y=x+2

Alik [6]

Y = 2x - 2 ⇒ 2x - y = 2 ⇒ 2x - y = 2
y = x + 2 ⇒ x - y = -2 ⇒ 2x - 2y = -4
 3y = 6
 3 3
 y = 2
 2x - 6 = 2
 +6 +6
 2x = 8
 2 2
 x = 4
 (x, y) = (4, 2)

8 0

3 years ago

Between which 2 numbers on a number line will √20 be found?

ehidna [41]

Answer:

Since the square root of 20 is around 4.5, we know that ≈4.5 is almost at the half mark between 4 and 5 on the number line.

4 0

1 year ago

A circle is inscribed in a square. A point in the figure is selected at random. Find the probability that the point will be in t

hram777 [196]

P of selecting point on the shaded region = shaded area/whole area
P( selecting point on the shaded ) = ( the four shaded circles ) / the whole square 
P of selecting point on the shaded = ( 4 * ( π * r^2 ) )/ x^2 
P of selecting point on the shaded = ( 4 * ( π * (x/4)^2 ) )/ x^2 
P of selecting point on the shaded = ( 4 * ( π * x^2/16 ) )/ x^2 
P of selecting point on the shaded = ( π * x^2/4 )/ x^2 
P of selecting point on the shaded = x^2( π/4 )/ x^2 
P( selecting point on the shaded ) = π/4 ≈ 0.7854 ≈ 79%
=80%
D is right option hope this helps

4 0

3 years ago