Answer:
Hi how are you doing today Jasmine
The probability of choosing a number that is not a multiple of 2 is P = 0.44
<h3 /><h3>How to find the probability?</h3>
We need to count the number of options for each digit.
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.
The total number of combinations is the product between the numbers of options:
C = 8*9*9 = 648
If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 4 options {1, 3, 5, 7}.
C = 8*9*4 = 288
Then the probability of selecting a 3 digit number that is not a multiple of 2 is:
P = 288/648 = 0.44
If you want to learn more about probability, you can read:
brainly.com/question/251701
D. The y-intercept of the function is (0, 5) and e. The function crosses the x-axis twice are true
It would be 1/5, 5/8, 2/3 because 1/5 is 24/120, 2/3 is 80/125, and 5/8 is 75/120
In this case were going to solve the question using "simple interst", so since were looking for the interest it will be I= PxRxT (I stands for "interest", P stands for "principal", R stands for "rate" and T stands for "time")
so P is $3000
R is 2%
and T is 3 years
so we'll have to turn our rate into a decimal which is 2% = .02
now to start the problem:
I= (3000)(.02)(3) (means 3000 x .02 x 3)
I= $180 is your answer
