now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,
factor 12t2 + 70t + 72 a= 12(t+3) (t+2) b= 2(3t+4)(2t+9) c= 2(3t+ 9) (2t+4) d= (6t+8)(2t+9)
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now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,
Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector = square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:
Where, A = area
r = radius = 3
Substituting values in the formula, we have:
The area of the sector = square units