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sasho [114]
2 years ago
5

The stopping distance for 10 cars traveling at 55 miles per hour is shown in the table above . What is the mean (average ) stopp

ing distance for the 10 cars ?

Mathematics
1 answer:
umka21 [38]2 years ago
8 0

Answer:

50

Step-by-step explanation:

Add all of the numbers and divide by the number of columns. Ex.

48+49+50+51+51= 250

250÷5= 50

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A baker recorded the number of batches of
azamat

Answer:

B. The lower extreme increased.

Step-by-step explanation:

From the original box and whisker plot, the lower extreme (minimum) is 5 ; The upper extreme, maximum is 15.

The number of batches baked on the eight day is 20. This exceeds tbe previous maximum value. Hence, upper extreme( maximum) value of the new plot will change from 15 to 20.

The lower extreme isn't affected as the obtained value isn't below 5.

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3 years ago
What is wrong with this solution
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Answer:

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Step-by-step explanation:

-5m/5 = -m, not m.

In step 2, both sides should be divided by -5, not by 5.

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Work out the gradient of the line joining the points (2, 3) and (5,7)
Debora [2.8K]

Answer:

The gradient of the line joining the points P(x,y) = (2,3) and Q(x,y) = (5,7) is \frac{4}{3}.

Step-by-step explanation:

The gradient of the line joining two distinct point on a plane is represented by the slope of a secant line (m_{PQ}), that is:

m_{PQ} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}} (1)

If we know that P(x,y) = (2,3) and Q(x,y) = (5,7), then the gradient of the line is:

m_{PQ} = \frac{7-3}{5-2}

m_{PQ} = \frac{4}{3}

The gradient of the line joining the points P(x,y) = (2,3) and Q(x,y) = (5,7) is \frac{4}{3}.

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3 years ago
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