Answer:
Reactive power is 1.152 VARs
Step-by-step explanation:
We are given that in a parallel circuit,
,R=47kΩ and 
=50kΩ.
reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.
Current through inductor=
milli amps=0.0048 A
Reactive power = (current flowing through inductor)X (Voltage across inductor)
Hence reactive power = 0.0048 X 240=1.152 VARs
Answer:
How do you find the equilibrium price with a supply and demand function?
To determine the equilibrium price, do the following.
Set quantity demanded equal to quantity supplied:
Add 50P to both sides of the equation. You get.
Add 100 to both sides of the equation. You get.
Divide both sides of the equation by 200. You get P equals $2.00 per box. This is the equilibrium price.
Answer:
11) .75 12) .65 13) .6 14) .4 15) a. .6 b. 4 16) .09 17) 9/100 18) .60 19) .20 10) .50
Step-by-step explanation:
Your'e welcome (;
Scale factor of area is the square of the scale factor of length
The required values are;
- The length of one sides of the garage was originally approximately <u>19.2 ft.</u>
- The length of one of the sides of the garage is now approximately <u>23.6 feet</u> long
- The percentage increase in length is approximately <u>22.5 %</u>
Reason:
The given parameters are;
The area of the square garage = 370 ft.²
The area of the new garage has 50% more space
Required;
Part A
The initial side length
The initial side length, given to the nearest tenth, <em>s</em>, is the square root of the area, <em>A</em>, given as follows;
- s = √(370 ft.²) ≈ 19.2 ft.
Part B
The side was increased by 50%, to give,
370 + 0.5×370 = 555
The new area of the garage = 555 ft.²
The side length of the new garage, s = √(555) ≈ 23.6
- The side of the garage now is 23.6 ft.
Part C
The percentage increase is given as follows;
- The percentage increase in length of the side of the garage is approximately 22.5 %
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