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baherus [9]
2 years ago
15

Solve for the indicated variable.

Mathematics
1 answer:
Hunter-Best [27]2 years ago
3 0

Answer:

<h3><u>1.</u>)</h3>

3n + 1 = 7n - 5

1 + 5 = 7n - 3n

6 = 4n

3/2 = n

<h3><u>2</u><u>.</u>)</h3>

2[x + 3(x - 1)] = 18

2[x + 3x - 3] = 18

2(4x - 3) = 18

8x - 6 = 18

8x = 12

x = 12/8

x = 3/2

<h3><u>3</u><u>.</u>)</h3>

6(y + 2) - 4 = -10

6y + 12 - 4 = -10

6y = -10 - 8

6y = -18

y = -3

<h3><u>4</u><u>.</u>)</h3>

2x² = 50

x² = 50/2

x = √25

x = 5

<h3><u>5</u><u>.</u>)</h3>

5 + 2(k + 4) = 5(k - 3) + 10

5 + 2k + 8 = 5k - 15 + 10

2k - 5k = -5 - 13

-3k = -18

k = 6

<h3><u>6</u><u>.</u>)</h3>

6 + 2x(x - 3) = 2x²

6 + 2x² - 6x = 2x²

-6x = 2x² - 2x² - 6

x = 1

<h3><u>7</u><u>.</u>)</h3>

2/3x - 18 = x/6

12(2/3x - 18 = x/6)

8x - 216 = 2x

8x - 2x = 216

6x = 216

x = 36

<h3><u>8.</u>)</h3>

x - 2/3 = 2x + 1/4

12(x - 2/3 = 2x + 1/4)

4x - 8 = 6x + 3

4x - 6x = 8 + 3

2x = 11

x = 11/2

<u>-TheUnknownScientist</u><u> 72</u>

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Graph y &gt; -1/3x+5<br><img src="https://tex.z-dn.net/?f=y%20%3E%20%20-%20%20%5Cfrac%7B1%7D%7B%203%20%7D%20x%20%2B%205" id="Tex
ad-work [718]

Explanation:

The function is y>-\frac{1}{3} x+5

To graph the function, let us find the x and y intercepts.

To find x-intercept, let us substitute y=0 in the function y>-\frac{1}{3} x+5

\begin{aligned}0 &=-\frac{1}{3} x+5 \\-5 &=-\frac{1}{3} x \\x &=15\end{aligned}

Thus, the x-intercept is (15,0)

To find the y-intercept, let us substitute x=0, we get,

\begin{aligned}&y=-\frac{1}{3}(0)+5\\&y=5\end{aligned}

Thus, the y-intercept is (0,5)

The graph has no asymptotes.

To plot the points in the graph, we need to substitute the values for x in the function y>-\frac{1}{3} x+5, to find the y-values.

The points are (-2,5.667),(-1,5.333),(1,4.667),(2,4.333),(3,4). The image of the graph and table is attached below:

6 0
2 years ago
HELP PLEASE BRAINLIEST!
7nadin3 [17]
A straight line can be drawn through all the points and the line passes through the point where x=0 and y=0. This best describes a graph of paired points that form a proportional relationship. You can tell this because the line passes directly through the origin (0,0). It also says that it is a straight line that passes through the points, so most likely the line will contain points that have a proportional relationship. Hope that helps :)
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How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points
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Answer: m=\frac{-30}{79},\ y=5.40

Step-by-step explanation:

Given

Points are \left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)

Convert mixed numeral to fraction

\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)

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\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}

Equation of line

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