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baherus [9]
3 years ago
15

Solve for the indicated variable.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

<h3><u>1.</u>)</h3>

3n + 1 = 7n - 5

1 + 5 = 7n - 3n

6 = 4n

3/2 = n

<h3><u>2</u><u>.</u>)</h3>

2[x + 3(x - 1)] = 18

2[x + 3x - 3] = 18

2(4x - 3) = 18

8x - 6 = 18

8x = 12

x = 12/8

x = 3/2

<h3><u>3</u><u>.</u>)</h3>

6(y + 2) - 4 = -10

6y + 12 - 4 = -10

6y = -10 - 8

6y = -18

y = -3

<h3><u>4</u><u>.</u>)</h3>

2x² = 50

x² = 50/2

x = √25

x = 5

<h3><u>5</u><u>.</u>)</h3>

5 + 2(k + 4) = 5(k - 3) + 10

5 + 2k + 8 = 5k - 15 + 10

2k - 5k = -5 - 13

-3k = -18

k = 6

<h3><u>6</u><u>.</u>)</h3>

6 + 2x(x - 3) = 2x²

6 + 2x² - 6x = 2x²

-6x = 2x² - 2x² - 6

x = 1

<h3><u>7</u><u>.</u>)</h3>

2/3x - 18 = x/6

12(2/3x - 18 = x/6)

8x - 216 = 2x

8x - 2x = 216

6x = 216

x = 36

<h3><u>8.</u>)</h3>

x - 2/3 = 2x + 1/4

12(x - 2/3 = 2x + 1/4)

4x - 8 = 6x + 3

4x - 6x = 8 + 3

2x = 11

x = 11/2

<u>-TheUnknownScientist</u><u> 72</u>

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Quadrilateral ABCD has vertices A (-3, 0), B (2, 4), C (3, 1), and D (-4, -3). Calculate the perimeter of the quadrilateral. Rou
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Perimeter of the Quadrilateral=20.78

Step-by-step explanation:

Perimeter of the Quadrilateral= AB+BC+CD+AD

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AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\

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         \sqrt{(3-2)^2+(1-4)^2} \\\\=\sqrt{1^2+(-3)^2} \\\\=\sqrt{1+9}\\\\ =\sqrt{10}

          =3.16

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AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16

Perimeter of the quadrilateral= AB+BC+CD+AD

             =6.40+3.16+8.06+3.16

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Step-by-step explanation:

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