Answer:
AC = (20+ 10q)
Step-by-step explanation:
Given that,
Total cost, TC = 20q + 10q²
We need to find AC i.e. average cost.
It can be solved as follows :

So, the value of AC is (20+ 10q).
4x + 2y = 8 (1)
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =

y = -x
<span>
Thus the gradient of the two equations are different and as such the two lines are not parallel</span>
B) When two lines are perpendicular, the product of their gradient is -1

p = (-2) * (-1)
p = 2
<span> ∴
the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
I think the best option is 24.
Answer:
x = -2
Step-by-step explanation:
Solve for x:
(2 (3 x - 4))/5 = -4
Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:
(5×2 (3 x - 4))/(2×5) = -4×5/2
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) (3 x - 4) = -4×5/2
5/2 (-4) = (5 (-4))/2:
(5×2 (3 x - 4))/(2×5) = (-4×5)/2
(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:
3 x - 4 = (-4×5)/2
(-4)/2 = (2 (-2))/2 = -2:
3 x - 4 = 5×-2
5 (-2) = -10:
3 x - 4 = -10
Add 4 to both sides:
3 x + (4 - 4) = 4 - 10
4 - 4 = 0:
3 x = 4 - 10
4 - 10 = -6:
3 x = -6
Divide both sides of 3 x = -6 by 3:
(3 x)/3 = (-6)/3
3/3 = 1:
x = (-6)/3
The gcd of -6 and 3 is 3, so (-6)/3 = (3 (-2))/(3×1) = 3/3×-2 = -2:
Answer: x = -2