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Firdavs [7]
2 years ago
14

Please solve this for me using substitution

Mathematics
1 answer:
Vinvika [58]2 years ago
6 0

<h2> <u>Explanation</u><u>:</u></h2>

\bf \underline{★Given-} \\

\textsf{4x + 5y = 8};

\textsf{5x + 4y = 12}

\bf \underline{★To\: find-} \\

\textsf{the value of x and y in equation?}

\bf \underline{★Solution-} \\

\sf \leadsto 4x + 5y = 8 - - - (i)

\sf \leadsto 5x + 4y = 12 - - - (ii)

By first equation,

\sf \leadsto 4x + 5y = 8

\sf \leadsto 4x = 8 - 5y

\sf \leadsto x = \dfrac{8 - 5y}{4}

\textsf{Now, we can find the original value of Y.}\\

\sf \leadsto 5x + 4y = 12

\sf \leadsto 5 \bigg( \dfrac{8 - 5y}{4} \bigg) + 4y = 12

\sf \leadsto \dfrac{40 - 25y}{4} + 4y = 12

\sf \leadsto \dfrac{40 - 25y + 16y}{4} = 12

\sf \leadsto \dfrac{40 - 9y}{4} = 12

\sf \leadsto 40 - 9y = 12(4)

\sf \leadsto 40 - 9y = 48

\sf \leadsto -9y = 48 - 40

\sf \leadsto -9y =  8

\sf \leadsto y = \dfrac{ -8}{9}

\textsf{Now, we can find the original value of X.}\\

\sf \leadsto 4x + 5y = 8

\sf \leadsto  4x + 5 \bigg( \dfrac{ -8}{9} \bigg) = 8

\sf \leadsto 4x - \dfrac{40}{9} = 8

\sf \leadsto \dfrac{36x - 40}{9} = 8

\sf \leadsto 36x - 40 = 8(9)

\sf \leadsto 36x - 40 = 72

\sf \leadsto 36x = 72 + 40

\sf \leadsto 36x = 112

\sf \leadsto x = \dfrac{112}{36}

\underline{\textsf{Answer-}}\\

Therefore, the values of x and y are -8/9 and 112/36 respectively.

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