Multiplying and dividing with conjugate of 2+i in the given expression, we get(3+ 4i)(2-i)/(2+i)(2-i)=(6-3i+8i-4i^2)/(4-i^2)=(10+5i)/(4+1)=(10+5i)/5=2+i=a+bi<span>Thus a=2</span>
ANSWER
B. The two middle coefficients add to the correct number but do not multiply to the correct number.
EXPLANATION
The given quadratic trinomial that Tina tries to factor is
Comparing to
we have a=10, b=-13 and c=-3
ac=-3×10=-30
We split the middle term so that their sum is -13.
Tina use
-10,-3
to get
-10x-3x
The sum is -13x alright but the product is not -30.
B is correct.
Answer:
The answer is A
Step-by-step explanation:
1 to the second power is 1 + 1 = 2
2 to the second power is 4 + 1 = 5
3 to the second power is 9 + 1 = 10
4 to the second power is 16 + 1 = 17
5 to the second power is 25 + 1 = 26
14n + 21
Just distribute the 7 to the 2n and the 3.
7(2n + 3)
(7 * 2n) + (7 * 3)
14n + 21
Please consider marking this answer as Brainliest to help me advance.
From the equation of a line;
y=mx+c
m=2
y=2x+c
Replacing for;
y=1
x=3
1=2*3+c
1=6+c
c=1-6
c=-5
<span>y=2x-5</span>
