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ra1l [238]
2 years ago
12

Lizzy wants to solve the equation 6(2x + 1) = 4x – 5. Which step would be an appropriate first step for Lizzy to take to solve f

or x?
Mathematics
1 answer:
e-lub [12.9K]2 years ago
7 0

Answer:

distribute parenthesis

Step-by-step explanation:

6(2x + 1) = 4x - 5 ← distribute parenthesis on left side

12x + 6 = 4x - 5 ( subtract 4x from both sides )

8x + 6 = - 5 ( subtract 6 from both sides )

8x = - 11 ( divide both sides by 8 )

x = - \frac{11}{8}

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On a number line what is the distance between -12 and 20 ??
KIM [24]

Answer:  Step-by-step explanation:

In order to answer this question you will need to find 2 distances and then add them to each other.

Begin at -29.  How far will you have to move to the right 29 in order to get to 0?

Now how far will you have to more to get from 0 to 100?

Draw an open number line to help you.

_____________________________________________________

-29                                           0                                                   100

Your first distance is 29.  Your second distance is 100.  The total distance is 129.

3 0
3 years ago
Please help answer all of 4 and 6
saul85 [17]

Answer:

The Points are too little for this many questions

Step-by-step explanation:

Make it like 25 Points then people will answer it

8 0
2 years ago
Did I do these two correctly?
natka813 [3]
Yes you did the equation on this page correctly.
7 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
Find the midpoint M of the line segment joining the points A= (-7, -6) and B= (1,8).
Marrrta [24]

Step-by-step explanation:

Use midpoint formula,

x = -6/2 = -3 , y=2/2 =1

(x,y)=(-3,1)

so , the coordinates of mid point of line segment is M (-3,1)

8 0
3 years ago
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