Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
1.D
2.B
Step-by-step explanation:
question 1
-2(2)²+1/3(2)
-7/6
question 2
(-4x-2)(2x)
-8x²-4x
Solution:

Answer:

<em>Hope this was helpful.</em>
Answer:
x ≈ 58.9
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
- [Right Triangles Only] tan∅ = opposite over adjacent
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use trig to find the missing side length.
<u>Step 2: Identify Variables</u>
<em>POV from the angle measure</em>
Angle = 23°
Opposite Leg = 25
Adjacent Leg = <em>x</em>
<em />
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitution [tangent]: tan23° = 25/x
- Multiply <em>x</em> on both sides: xtan23° = 25
- Isolate <em>x</em>: x = 25/tan23°
- Evaluate: x = 58.8963
- Round: x ≈ 58.9
Answer:
x = 
Step-by-step explanation:
Using the rule of logarithms
log x - log y = log (
)
x = n ⇒ x = 
Given
(9x) -
3 = 3
(
) = 3
3x = 3
3x = 2³ = 8 ( divide both sides by 3 )
x = 