Answer:
The acceleration in the system and in the rope is same as 5.88 m/s2.
Step-by-step explanation:
The figure shows two blocks of m1 = 0.8 Kg and m2 = 0.2 kg if the block of mass m2 is dragged by the block of mass m1 calculate the acceleration of the system and the acceleration of the rope
Let the acceleration is a and the tension in the string is T.
Use Newton's second law

part a- x + 3.25 x + 3.25 3x - 2 3x - 2 3x - 2
part b- 21x
part c- 7.75
Let
x--------> the degree of difficulty of the dive
we know that
1) The highest and the lowest scores are dropped
so
highest scores=
lowest scores=
the remaining scores=![[7.5, 8.0, 7.0, 7.5, 7.0]](https://tex.z-dn.net/?f=%20%5B7.5%2C%208.0%2C%207.0%2C%207.5%2C%207.0%5D%20)
2) Find the total of the remaining scores
![=[7.5+8+7+7.5+7]\\ =37](https://tex.z-dn.net/?f=%20%3D%5B7.5%2B8%2B7%2B7.5%2B7%5D%5C%5C%20%3D37%20)
3) The total of the remaining scores is multiplied by the degree of difficulty of the dive
so

4) This product is multiplied by .6 to determine the final score
![[37*x]*0.6=77.7\\ 22.2*x=77.7\\ x=3.5](https://tex.z-dn.net/?f=%20%5B37%2Ax%5D%2A0.6%3D77.7%5C%5C%2022.2%2Ax%3D77.7%5C%5C%20x%3D3.5%20)
therefore
the answer is
the degree of difficulty of the dive is 
Slope is -3/5x in this equation
Answer:
B
Step-by-step explanation:
-1+(-6)