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tangare [24]
3 years ago
13

Solve for x:

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer:

x = 5.95

Step-by-step explanation:

Given

\frac{x}{1.7} = 3.5

Multiply both sides by 1.7 to clear the fraction

x = 1.7 × 3.5 = 5.95

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F(13)=45,000(0.9)^13
Nadusha1986 [10]

Answer:

About 879.877

Step-by-step explanation:

To find f,

f(13) = 45,000(0.9)^13

13f = 45,000(0.25418658283)

13f = 11438.3962274

f = 879.877

Please tell me I did this the right way, Thanks!

3 0
3 years ago
Janie receives an allowance of $3 per week. In addition, she can earn $2 for each chore she does. This week, she wants to earn e
Lilit [14]
Let us say that the number of weeks is "x" and the number of chores is "y".

If we state an algebraic expression for Janie's allowance it would be

3x+2y=13

However, there are two variables, hence many answers. To solve this problem, there must be more information about the relation between x and y.
6 0
2 years ago
Read 2 more answers
ALGEBRA Find mZA in ABC if mZB = 38º and mZC = 38º.
ValentinkaMS [17]

Answer:

d

Step-by-step explanation:

dddddddddddddddddddddddddddd

6 0
3 years ago
11. Write the balanced equation for the reaction of HC2H3O2, with Al(OH)3 to form H2O and Al(C2H302)3:
Kamila [148]

Answer:

74.36 g of aluminium acetate.

730.27g of aluminium acetate.

- to the nearest hundredth.

Step-by-step explanation:

Acetic acid is usually written as CH3COOH.

a. 6CH3COOH + Al(OH)3 ---> Al(CH3COO)3 + 9H2O

So 6 moles of acetic acid produce 1 mole of aluminium acetate.

Using the molecular masses

6*( 1.008*4 + 12.011*2 + 16 *2) g acetic acid gives (26.98+3(36.032+ 2*12.011)

348.228 g acetic acid gives 207.142 g Al acetate.

So 125 g gives (207.142 / 348.228) * 125

= 74.36 g of aluminium acetate.

b.

(26.98 + 3*16 + 3 * 1.008) g  of Al(OH)3 gives 207.142 g Al acetate

78.004 g gives 207.142 g Al acetate

275 g gives   (207.142 / 78.004) * 275

= 730.27g Al acetate.

7 0
3 years ago
Find angle A and angle B..​
ExtremeBDS [4]

Step-by-step explanation:

\sf{\bold{\blue{\underline{\underline{Given}}}}}

\tt{\angle{c}=110°}

and,

\tt{BC=AC}

⠀⠀⠀⠀

\sf{\bold{\red{\underline{\underline{To\:Find}}}}}

☆Find the \angle{B} ~and~\angle{A}

\sf{\bold{\purple{\underline{\underline{Solution}}}}}

Here,

BC =AC

so,

⠀⠀⠀

\angle{A}=\angle{B}

we know that,

\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}

But \angle{C}=110°(Ģìvéñ)

so..

\angle{A}+\angle{B}+110°=180°

\angle{A}+\angle{A}+110°=180°

\because{\angle{A}=\angle{B} }

2\angle{A}=180°-110°

2\angle{A}=70°

\angle{A}=\dfrac{70°}{2}

\boxed{\orange{\angle{A}=35°}}

But...

\angle{A}=\angle{B}

soo,

\boxed{\orange{\angle{B}=35°}}

\sf{\bold{\green{\underline{\underline{Answer}}}}}

⠀⠀⠀⠀

\boxed{\green{\angle{A}=35°}}

\boxed{\green{\angle{B}=35°}}

7 0
2 years ago
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