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Tcecarenko [31]
3 years ago
6

I need helpp its my final exam​

Mathematics
2 answers:
Mashcka [7]3 years ago
7 0

Answer:

hey i believe that your answer is A. without having to do the math if you look at it you can tell that its bigger then options B and C so those are not it.  and  it is to small to be D. so with that said your answer is A have a nice dy and good luck!

Step-by-step explanation:

dem82 [27]3 years ago
7 0
This is the exterior angle theorem meaning the two angles in the triangle is equal to the outer angle of the angle. So you would set your equation to (3x+4) + 58 = 12+8x

Solve for x then plug the x back into the 12+8x equation to get your angle
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Solve for x and explain the steps in your answer. Please Help :/
Solnce55 [7]
I believe the answer is -25/6 :)
7 0
3 years ago
Mrs. DeMarco wants to estimate the length of her porch so she knows how much paint to buy. What is the best benchmark for her to
Zigmanuir [339]
The answer c ,I hope I’m right
8 0
3 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
How do you write the difference of a number and eight, divided by ten
ch4aika [34]

Answer:

(x-8)/10

Step-by-step explanation:

-------

7 0
4 years ago
Read 2 more answers
Dy/dx=(x+1)^2 in problem solve the given differential equation by separation of variable
Brilliant_brown [7]
The derivative of (x+1)^2, for this you use the chain rule, to get 2x+2.
3 0
4 years ago
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