<h3><u>Question:</u></h3>
Juan and raj cut up a banana to put on cereal. juan puts 1/7 of the banana on his bowl of cereal, and raj puts 2/5 of the banana on his bowl of cereal.
what fraction of the banana did juan and raj put on their cereal altogether?
a. 2/35 banana
b. 3/12 banana
c. 3/7 banana
d. 19/35 banana
<h3><u>Answer:</u></h3>
Juan and Raj altogether put 19/35 banana
<h3><u>Solution</u>:</h3>
Given that, Juan and Raj cut up a banana to put on cereal
We have to find the fraction of banana put by Juan and Raj altogether
This means, we have to add both the fractions
Thus they put 
of banana by Juan and Raj altogether
Not completely sure on the symbols, but I think it is 5 x ( 22 - 9 x 2 ) - 2 ( 3 x 2 x 4 ) x 7 = 136. It doesn't really match the answers, so my advice is that you use a calculator for this one, or as the person/teacher who gave you the problem how to solve it.
Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
it would be c 9/25 and 9/25
It equals 23 degrees Fahrenheit. So -5c=23f
