Solve the following equation:z+9/3(z+5) = -2

Mathematics

1 answer:

mezya [45]3 years ago

5 0

Answer:

Hence, the value of z is -39/7.

Step-by-step explanation:

$\sf \leadsto \dfrac{z + 9}{3(z + 5)} = -2$

$\sf \leadsto \dfrac{z + 9}{3z + 15} = -2$

$\sf \leadsto z + 9 = -2(3z + 15)$

$\sf \leadsto z + 9 = -6z - 30$

$\sf \leadsto z + 6z = -30 - 9$

$\sf \leadsto 7z = -39$

$\sf \leadsto z = \dfrac{-39}{7}$

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a pentegon can be divided into five congruent triangles as shown. the function y=5 tan theta models the height of each triangle.

g100num [7]

We are required to calculate the area of the pentagon whose height is given by y=5 tan theta
where; theta=54°
but
tan theta=[opposite]/[adjacent]
thus
opposite=adjacent tan theta
since
5tan54=opposite
adjacent=5
Therefore the base of the pentagon will be
(5+5)=10
Area of a triangle is given by:
A=1/2(base*height)sin theta
The area of one triangle forming the pentagon will be:
A=1/2*(10*5tan54)*sin54
A=27.84 square units
Thus the area of pentagon will be:
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=27.84*5
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