The angles ACD and Angle ABE are congruent so there measure is equal.
3x+14=50
3x= 50-14
3x= 36
X= 36/3=12
The given points are
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or

The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:

The magnitude is √(10).
Answer:
The cost per ticket is<u> constant</u>.
Step-by-step explanation:
Given:
It costs $20 for 4 play tickets and $35 for 7 play tickets.
Now, to get whether cost per ticket is constant or not.
So, if the cost per ticket is constant that means the cost of ticket for a play or more is fixed, non-varying and it does not change.
Now, we check it:
4 play tickets costs = $20.
1 play tickets costs = $20 ÷ 4 = $5.
So, 7 play tickets costs = $5 × 7 = $35.
Thus, the cost of ticket for play is not changing and it is constant.
So the cost per ticket is constant.
Therefore, the cost per ticket is constant.
Answer:
a=55
b=55
c=125
d=125
e=55
f=55
g=125
Step-by-step explanation:
Answer:
14/33
Step-by-step explanation:
The total amount of beads is 8+4 = 12. 8 of these are black beads, so that is what we want, so 8/12 or 2/3. For the second one, one black bead is already taken so 8-1 = 7 are left and for the total 12 - 1 = 11 are left, so 7/11. Multiply this by 2/3 and we get 14/33.