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larisa [96]
2 years ago
7

Hey That last question is A LOT OF POINT'S

Mathematics
1 answer:
sergejj [24]2 years ago
5 0

Answer:

1. 7x

2. 8x - 1

3. 12 + 6x

4. 4 - 7x

5. 13x - 7

Step-by-step explanation:

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Which statements are true about the polynomial 4x3 – 6x2 + 8x – 12?
olga2289 [7]

1. correct- factor: 4

2. correct- factor: 4

3. Incorrect- The polynomial is not prime, and the factored polynomial is 4(2x-3)

4. Incorrect

7 0
3 years ago
Write a verbal expression for:<br> 20+6
Helen [10]

what is the result of the addition of 20 and 6

8 0
2 years ago
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A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.
baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

5 0
3 years ago
#2
sergey [27]
It is the third onne
4 0
3 years ago
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PLEASE PLEASE HELP ME:(( I NEED WORKING AS WELL
mr Goodwill [35]

the equation of the line has form

y=kx+b

\left \{ {{5=k*0+b} \atop {9=k*2+b}} \right. \\b=5\\9=2k+5\\2k=4\\k=2, so

y=2x+5

The second line is parallel to the first and runs 7 units lower, so b=5

0=1k+5\\k=-5\\y=-5x+5

8 0
3 years ago
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