Answer:
La mayor tiene 61 años.
Step-by-step explanation:
Sea x,y,z la edad de la mayor, intermedio y la menor respectivamente.
Tenemos las siguientes ecuaciones:
(la suma de las edades es 127)
(la mayor tiene 30 años más que la menor)
La frase "y la del intermedio 26 menos que la menor" no tiene sentido, puesto que esto implicaría que la del intermedio es menor que la menor. Luego se asume que la frase ha de ser "y la del intermedio 26 menos que la mayor"
(la del intermedio tiene 26 menos que la mayor).
La segunda ecuación se traduce a x-30 =z. Si reemplazamos todo en la primera ecuación obtenemos
![x+(x-26)+(x-30) = 127](https://tex.z-dn.net/?f=x%2B%28x-26%29%2B%28x-30%29%20%3D%20127)
Obtenemos la ecuación
![3x-56 = 127](https://tex.z-dn.net/?f=3x-56%20%3D%20127)
Sumando 56 a ambos lados y dividiendo por 3, obtenemos
![x = \frac{127+56}{3} = 61](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B127%2B56%7D%7B3%7D%20%3D%2061)
Es decir la mayor tiene 61 años.
Answer:
9/25
Step-by-step explanation:
3 novels , 1 bio , 1 poetry = 5 books
P( novel) = novels / books
= 3/5
Book is returned
3 novels , 1 bio , 1 poetry = 5 books
P( novel) = novels / books
= 3/5
P(novel, return, novel) = 3/5 * 3/5 = 9/25
This is the the concept of trigonometry, to get the sine value of the the function given we shall proceed as follows;
Using Pythagorean theorem, the hypotenuse of the triangle will be found as follows;
The side length will be 8 units since the y-coordinate is -8
The side width will be 3 units since the x- coordinate is 3
c^2=a^2+b^2
c^2=(3)^2+(-8)^2
c^2=9+64
c^2=73
c=sqrt(73)
Therefore the sine value will be:
sin x=3/sqrt(73)
multiply both numerator and denominator by sqrt(73) we get:
sin x=(3√73)/73
Therefore the answer is A]
Answer:
![\left[\begin{array}{ccc}7\\4\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C4%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
To find the product of two matrices we need to multiply the elements of each row of the first matrix by the elements of each column in the second matrix. Then we should add the products. Then:
×
=
= ![\left[\begin{array}{ccc}7\\4\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C4%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
The term "x" refers to the multiplication sign.
Then, the solution is ![\left[\begin{array}{ccc}7\\4\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C4%5C%5C2%5Cend%7Barray%7D%5Cright%5D)