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Tanya [424]
3 years ago
7

Write an equation of the line with a slope of −1/2 and a y-intercept of 1.

Mathematics
1 answer:
masha68 [24]3 years ago
5 0

Answer:

y=-1/2x+1

Step-by-step explanation:

y=mx+b

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Solve the following equation fro g:2(g-h)=b+4
monitta
2g - 2h = b + 4
2g = b + 4 + 2h
g = (b + 4 + 2h) / 2
4 0
3 years ago
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I<br> 8. Classify 8 as a perfect square, a perfect cube, both, or neither.
Murljashka [212]

Answer:

It's a perfect cube, but not a perfect square.

Step-by-step explanation:

2^3 = 8, meaning 8 is a perfect cube. But since 2^2 = 4 and 3^2 = 9, and 8 is in between, 8 is not a perfect square.

I hope this helped.

7 0
3 years ago
5x² + 3y when x =-2 and y = 10​
Vera_Pavlovna [14]

Answer:

50

Step-by-step explanation:

When a number is next to a variable, such as 5x, this means you will multiply them(five times x). With x being -2, we will multiply -2 x -2 = 4. the exponent tells you how many times to multiply a number by itself. If the exponent was 5, we would multiply 2 by itself 5 times to get 10. Since we got 4 for our answer, we will multiply that by since it was an exponent and we multiply it. 4 x 5 = 20. Since we know that we multiply numbers next to variables, we will multiply 3y or 3(10). 3 x 10 = 30. Add this to 20 to get your answer. 20 + 30 = 50.

Hope this helps :)

6 0
3 years ago
If AC = 2x + 3 and DB = 4x - 1, find x.
Talja [164]
The answer is x= 5 it’s 5
6 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
4 years ago
Read 2 more answers
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