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2 years ago

Pls help. This is due today!

Mathematics

1 answer:

JulijaS [17]2 years ago

4 0

Answer:

goodluck

Step-by-step explanation:

I got it from another person I hope it helps

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How do you solve x+2a=16+ax-6a ?

nasty-shy [4]

X+2a = 16+aX-6a
8X - 16 = aX-2a
8(X-2) = a(X-2)
(X-2)/(X-2) = a/8
1 = a/8
a= 8

3 0

2 years ago

Angel bought 8 oranges and 11 apples for a total of $15.22.He knows that each orange cost $0.50 and reasoned that each Apple mus

Schach [20]

Oranges = x
apples = y

8x + 11y = 15.22
x = 0.50

8(0.50) + 11y = 15.22
4 + 11y = 15.22
11y = 15.22 - 4
11y = 11.22
y = 11.22/11
y = 1.02 <== cost of each apple

3 0

3 years ago

Read 2 more answers

A statement can help you organize the numbers to answer a question about percents

Semenov [28]

Answer:

$50 is 27.02% of $185.

Step-by-step explanation:

Money spent on clothing = $50

Money spent on Groceries = $100

Money spent on Gas = $35

Total money spent = $185

Our question is to find the percentage of total money that is spent on clothing.

Percentage money on clothing = $\frac{Money spent on clothing}{Total money}$ × 100

= $\frac{50}{185}$ × 100

= 27.02% (approx)

Hence, $50 is 27.02% of $185.

5 0

2 years ago

Read 2 more answers

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago

50a3b-8ab factor the expression completely. part a: factor out the gcf (5 points) part b: factor the difference of perfect squar

dem82 [27]

Answer:

Step-by-step explanation:

50a³b = 2⋅5²a³b

8ab = 2³ab

GCF = 2ab

50a³b - 8ab = 2ab(5²a² - 2²)

5²a² - 2² = (5a - 2)(5a + 2)

8 0

2 years ago