You can set up an system of equations
x=2y+8
x-y=25

Substitute x in to the second equation
2y+8-y=25
y+8=25
y=17

Substitute the y back in to the first equation.
x=2(17)+8=42

7 0

3 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago

A candy company can make 360 pounds of chocolate in 6 hours how much can they make in 10 hours

LiRa [457]

Answer:

600

Step-by-step explanation:

divide 360 by 6 and you get how many pounds that can make in one hour.

which is 60 so then you multiply 60 by 10 and get 600

3 0

3 years ago

Please help i’ll give brainliest

Mekhanik [1.2K]

Answer:

Organisms that break down dead or decaying organisms

Step-by-step explanation:

Hope this helps :b

4 0

3 years ago

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