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ludmilkaskok [199]
3 years ago
13

20 points show work pls im in a hurry

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer: since it doesnt say 620 is included , we can conclude that x>620, not x>=620 so the 8th week would be cut just short, so answer is 7

aka

fewer than 8 weeks

Step-by-step explanation:

1200-620=580

580/72.50=8

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What is the answer to the following problem:<br> 6÷2(1+2)=?
maksim [4K]
Hi, Soldier23!
6/2(1+2)
6/2(3)
6/2=3
3*3=9
I hope this helps;)

7 0
3 years ago
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The domain of f(x)=4x is ____ the range of f(x) = 4^x is ____
Vesna [10]

Answer:

domain: all real numbers

range: y>0

Step-by-step explanation:

took it

6 0
4 years ago
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E<br>_ = 3 what is e<br>2 <br>im giving good
notsponge [240]

Answer:

e=2

Step-by-step explanation:

multiply both sides by 2 to get the variable by itself.

e=6

3 0
3 years ago
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Carlos and Ana were asked to find an explicit formula for the sequence -10,-4,2,8,...−10,−4,2,8,...Minus, 10, comma, minus, 4, c
mars1129 [50]

Answer:

Ana is correct

Step-by-step explanation:

Given

Sequence:\ -10, -4, 2,8

Carlos; f(n) = -10 + 6n

Ana; f(n) = -10 + 6(n-1)

Required

Determine who is right?

To do this, we simply test each sequence.

For Carlos:

When n = 1

f(1) = -10 + 6 * 1 = -10 + 6 = -4

When n = 2

f(2) = -10 + 6 * 2 = -10 + 12 = 2

<em>This is incorrect because the first and second term of the sequence are -10 and -4 not -4 and 2</em>

<em></em>

For Ana:

When n = 1

f(1) = -10 + 6(1-1) = -10 + 6*0 = -10 + 0 = -10

When n = 2

f(2) = -10 + 6(2-1) = -10 + 6*1 = -10 + 6 = -4

When n=3

f(3) = -10 + 6(3-1) = -10 + 6*2 = -10 + 12 = 2

When n = 4

f(4) = -10 + 6(4-1) = -10 + 6*3 = -10 + 18 = 8

This is correct.

<em>Hence, Ana is correct</em>

8 0
3 years ago
Read 2 more answers
The amount is 2.88 is ( percent of what price?
Ket [755]

Answer:

Discount = Original Price x Discount %/100

Discount = 2.88 × 1/100

Discount = 2.88 x 0.01

You save = $0.03

Final Price = Original Price - Discount

Final Price = 2.88 - 0.0288

Final Price = $2.85

4 0
4 years ago
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