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ExtremeBDS [4]
3 years ago
10

Michael has $15 and wants to buy a combination of school lunches to feed at least three classmates. A sandwich costs $2, and hot

lunch costs $3. This system of inequalities models the scenario: 2x + 3y ≤ 15 x + y ≥ 3 Part A: Describe the graph of the system of inequalities, including shading and the types of lines graphed. Provide a description of the solution set. (4 points) Part B: Is the point (5, 1) included in the solution area for the system? Justify your answer mathematically. (3 points) Part C: Choose a point in the solution set and interpret what it means in terms of the real-world context. (3 points)
Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer:

he can get 4 hot lunch for him qnd his class mate so he will have $3 more

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At the beginning of the month, there were 80 ounces of peanut butter in the pantry. Since then, the family ate 0.3 of the peanut
givi [52]

Answer:

B i think

Step-by-step explanation:

you are supposed to multiply the 80*.3 and that will give you 24 and subtract from 80 but im not sure

sorry if i got this wrong

4 0
3 years ago
Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (0, 11, −8) and
NNADVOKAT [17]

Answer:

The vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

Step-by-step explanation:

It is given that the line passes through the point (0,11,-8) and parallel to the line

x=-1+4t

y=6-4t

z=3+6t

The parametric equation are defined as

x=x_1+at,y=y_1+bt,z=z_1+ct

Where, (x₁,y₁,z₁) is point from which line passes through and <a,b,c> is cosine of parallel vector.

From the given parametric equation it is clear that the line passes through the point (-1,6,3) and parallel vector is <4,-4,6>.

The required line is passes through the point (0,11,-8) and parallel vector is <4,-4,6>. So, the parametric equations for the line are

x=4t

y=11-4t

z=-8+6t

Vector equation of a line is

\overrightarrow {r}=\overrightarrow {r_0}+t\overrightarrow {v}

where, \overrightarrow {r_0} is a position vector and \overrightarrow {v} is cosine of parallel vector.

\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)

Therefore the vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

3 0
3 years ago
Round the decimal 0.635 to the nearest hundredth
xeze [42]

Answer:

0.64

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What are the roots of x2 + 10x + 29 = 0?
scoundrel [369]
X² + 10x + 29 = 0
x = -(10) ± √((10)² - 4(1)(29))
                       2(1)
x = -10 ± √(100 - 116)
                     2
x = -10 ± √(-16)
               2
x = -10 ± 4i
            2
x = -5 ± 2i
x = -5 + 2i    or    x = -5 - 2i

THe roots of the function is 5 ± 2i.
3 0
3 years ago
Read 2 more answers
FH is the altitude to the hypotenuse EG. what is the length of FH. Really need some help with this!
Leviafan [203]

Answer:

Option A is correct

Step-by-step explanation:

Given: FH is the altitude to the hypotenuse EG

To find: length of FH

Solution:

According to Pythagoras theorem, square of hypotenuse is equal to sum of squares of other two sides.

In \Delta EHF,

\angle EHF=90^{\circ}

So,

EF^2=EH^2+FH^2

Put EH = 6 units and EF = 7 units

7^2=6^2+FH^2\\49=36+FH^2\\49-36=FH^2\\13=FH^2

Option A is correct

Take square root on both sides

FH=\sqrt{13}=3.606\,\,units

6 0
4 years ago
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