Answer:
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- <em><u>Line</u></em><em><u> </u></em><em><u>AE</u></em><em><u> </u></em><em><u> </u></em><em><u>&</u></em><em><u> </u></em><em><u> </u></em><em><u>Line</u></em><em><u> </u></em><em><u>AD</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>same</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>measurement</u></em><em><u>.</u></em>
I believe the answer is C) Infinitely many solutions. I'm not the greatest at these types of questions, so I apologize, I could be wrong.
Hopefully that helped! :)
The answers are x=4 and y=323/2
1) 40/2x-3=8
Multiply both sides by 2x-3 to get rid of fraction
40= 8(2x-3)
Distribute 8
40= 16x-24
Add 24 to both sides
64=16x
Divide by 16
4=x
2) 2y-3/40=8
Multiply both sides by 40 to red rod of fraction
2y-3=320
Add 3 to both sides
2y= 323
Divide by 2
Y=323/2
Now just describe the differences in solving them
FYI / means fraction, right after the slash is bottom of fraction
Answer:
The dimensions of the piece of metal can be represented by x and x+10.
Now, 2 in squares are being cut out of each corner.
So the new dimensions are x-4 (2in from each side) and x+10-4 or x+6.
When you fold it up, the height becomes 2 and the base has dimensions x-4 and x+6. Now plug this into the volume formula.
V=l*w*h
1302 = (x+6)(x-4)(2)
651 = x2+2x-24
0 = x2 + 2x-675
0 = (x+27)(x-25)
x=-27 reject since lengths cannot be negative or x=25.
So your original dimension for the piece of metal are 25 by 35.
Step-by-step explanation:
Find the values of x and y. a.x=90,y=47 b.x=43,y=47 c.x=47,y=43 d.x=90,y=43