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sergey [27]
3 years ago
8

How do I Graph y=2/3? (Without the fraction form)

Mathematics
2 answers:
RoseWind [281]3 years ago
7 0

\huge\boxed{\boxed{Hi\;there!}}

First of all, the slope of the line y=2/3 is 0, which means the line is horizontal.

Next, 2/3 is the y-intercept of the line (where the line touches the y-axis)

The line touches the y-axis at (0, 2/3) (or, 0.66667 in decimal form)

\huge\bold{Hope\;it\;helps\;you!\;Good\;luck!}}

\rule{250pt}}\huge\rm{StillEnjoyingLife :)

Greeley [361]3 years ago
3 0

Answer:

Here you go! :) (Its at (0,2/3)

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Arithmetic Sequence.<br><br>What is the explicit formula for -39, -139, -139, -339?​
creativ13 [48]

Answer:

  an = -39 -100(n -1)

Step-by-step explanation:

The given sequence can be described by a 3rd degree polynomial.* However, we suspect a typo, and that your intention is to have a formula for the arithmetic sequence ...

  -39, -139, -239, -339

This has a first term a1 = -39, and a common difference d = -100.

The model for the explicit formula is ...

  an = a1 +d(n -1)

Filling in the given values, the formula you seek is ...

  an = -39 -100(n -1)

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* That polynomial is ...

  an = 50n^3 +350n^2 -800n +461

This gives a sequence that starts ...

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dexar [7]
The answer is B
step by step explanation:
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Mademuasel [1]

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7/2

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(3,2) (5,9): Slope -->

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Write the equation of a line that is parallel to y=4 and passes through the point (-2,7)
Phoenix [80]

Answer:

Y= 2X+8

Step-by-step explanation:

Compare the given line with y=mx+c will give the slope of the parallel line as 2. Equation of new line in point slope form is y-y1 = m(x-x1). So y-4 = 2 (x+2) will give you Y= 2X+8

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3 years ago
PLEASE HELP ME I ASAP<br><br>I WILL MARK YOU BRAINLIEST
kramer
<h3>Function 1 : </h3>

Observe the abscicca and ordinates

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>y-coordinate</em><em> </em><em>is</em><em> </em><em>ordinate</em><em> </em><em>and</em><em> </em><em>x-coordinate</em><em> </em><em>is</em><em> </em><em>abscicca</em><em>.</em>

  • The ordinate having 0 as abscicca in function 1 is (0,1), Thus.. The y-intercept is 1

<h3>Function 2 : </h3>

Observe the graph and mark the point where function meets y-axis

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>point</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>meets</em><em> </em><em>y-axis</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>y-intercept</em><em>.</em>

  • The point where the function meets is (0,1). Therefore, The y-intercept of function 2 is also 1

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em><u>Thus, Option C is the correct choice!!~</u></em>

7 0
3 years ago
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