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Ad libitum [116K]
3 years ago
13

Find the difference quotient for the function f(x)=−5x−3f(x)=−5x−3. simplify your answer as much as possible.

Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0
Difference quotient = [f(x+h) - f(x)]/h

[-5(x+h) -3 - (-5x -3)]/h
[-5x -5h -3 + 5x +3]/h
[-5h]/h
-5
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Let f and g be functions. (a) The function (f + g)(x) is defined for all values of x that are in the domain(s) of ____________.
krok68 [10]

Answer:

a) for all values of x that are in the domains of f and g.

b) for all values of x that are in the domains of f and g.

c) for all values of x that are in the domains of f and g with g(x)≠0

Step-by-step explanation:

a) By definition (f+g)(x)=f(x)+g(x). Then x must be in the domain of f and g.

b) By definition (fg)(x)=f(x)g(x).  Then x must be in the domain of f and g.

c) By definition (f/g)(x)=f(x)/g(x).  Then x must be in the domain of f and g and g(x) must be different of 0.

5 0
3 years ago
Joint ownership does not guarantee there will be no problems in transferring property, true or false?
Natasha_Volkova [10]
This is true.
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3 0
3 years ago
Read 2 more answers
a boy walks along at a constant speed of 3 meters per second for 1 minute. how far does he travel during this time?
Nadusha1986 [10]
The boy walks at a constant speed V=3 m/s where V is his velocity
1 minutes has 60 seconds
Thus we conclude during 1 minute he travels :
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5 0
3 years ago
I didn't understand this to be honest I thought I had to find what jm and lm were together and then subtract from the whole tota
prisoha [69]

Answer:

The correct answer is 3x-2

Step-by-step explanation:

It gives you the expression for JM and LM, and it asks for JL. Therefore, if you take away LM from JM, you are left with JL. You must subtract 2x-6 from 5x-8.

∴5x-8-(2x-6)

Do not forget to distribute the negative since you are subtracting, so instead of subtracting 6 from 8, you will be adding 6 to 8 because two negatives make a positive.

7 0
3 years ago
Which simplifications of the powers of i are correct? There may be more than one correct answer.
fredd [130]

\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark

\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes

6 0
3 years ago
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