The average acceleration of an object is calculated as the final speed minus the initial speed divided by the elapsed time.
So:
![a = \frac{V_f-V_0}{T_2-T_1}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7BV_f-V_0%7D%7BT_2-T_1%7D)
Where
= final speed
= initial speed
= elapsed time.
Thus:
The acceleration of the cyclist is:
![a = \frac{8-0}{3}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B8-0%7D%7B3%7D)
a = 2.667![m / s ^ 2](https://tex.z-dn.net/?f=m%20%2F%20s%20%5E%202)
The acceleration of the car is:
![a = \frac{30-0}{8}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B30-0%7D%7B8%7D)
a = 3.75 ![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
The average acceleration of the car is higher than the average acceleration of the cyclist.
The height must be 12.8.
We first find the volume of paint in the larger can. The formula for the volume of a cylinder is V=πr²h. Using the radius and height of the large can, we have
V=3.14(8²)(20) = 4019.2
Since he has 1/4 of the can left, he has 4019.2/4 = 1004.8 cm³ of paint.
Using this volume and the dimensions of the smaller can, we work backward to find the height of the paint in the can:
1004.8 = 3.14(5²)h
1004.8 = 78.5h
Divide both sides by 78.5:
1004.8/78.5 = 78.5h/78.5
12.8 = h
Answer:
We are given the function h(y) = 4|y + 2| - 3
So, to get the value of h(-8), we just have to replace the y in the equation with -8
<em>In functions, the variable in the parentheses next to the name of the function is the variable we have to replace since the function is defined in the terms of that one variable. When you do more advanced questions, you will encounter functions with more than 1 variable</em>
<em />
h(y) = 4 | y + 2 | - 3
replacing y with -8 to get the output in terms of -8
h(-8) = 4 | -8 + 2 | -3
h(-8) = (4 * 6) - 3
h(-8) = 24 - 3
h(-8) = 21
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If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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