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sukhopar [10]
3 years ago
12

What is cos 0 when sin 0

Mathematics
1 answer:
taurus [48]3 years ago
4 0

Answer:

Cos θ = √7/3

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine θ = √2 / 3

Cos θ =?

Recall

Sine θ = Opposite / Hypothenus

Sine θ = √2 / 3

Thus,

Opposite = √2

Hypothenus = 3

Next, we shall determine the Adjacent. This can be obtained as follow:

Opposite = √2

Hypothenus = 3

Adjacent =?

Hypo² = Adj² + Opp²

3² = Adj² + (√2)²

9 = Adj² + 2

Collect like terms

9 – 2 = Adj²

7 = Adj²

Take the square root of both side

Adjacent = √7

Finally, we shall determine the value Cos θ. This can be obtained as follow:

Adjacent = √7

Hypothenus = 3

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = √7/3

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I need help finding Sin B, Cos B, and Tan A for a geometry problem. please help meee
Scilla [17]

Answer:

Sin B = 5/13

Cos B = 12/13

tan A = 12/5

Step-by-step explanation:

Sin B = opposite side/ hypotenuse

Sin B = 5/13

Cos B = adjacent side / hypotenuse

         = 12/13

tan A = opposite side /adjacent side

          = 12/5

6 0
3 years ago
Please help!
laila [671]
Because
\frac{f(x)}{x-3} = 2x^{2} + 10x - 1
therefore
f(x) = (x-3)(2x² + 10x - 1) + k, where k =  constant.

Because f(3) = 4, therefore k =4.
The polynomial is
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      = 2x³ + 4x² - 31x + 7

Answer:  f(x) = 2x³ + 4x² - 31x + 7

6 0
3 years ago
What is the volume of a cylinder with a radius of 4cm and a height of 8cm
MissTica

Answer: V=πr^2h=π·4^2·8≈402.12386cm^2

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Read 2 more answers
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
Evaluate 0 × |-6|. ......
kupik [55]

Answer:

0

Step-by-step explanation:

Any value multiplied by zero equals zero , thus

0 × | - 6 | = 0

6 0
3 years ago
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