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nexus9112 [7]
2 years ago
9

The local newspaper has letter to the editor from 20 people.If this number represents 5% of all of the newspaper’s readers,how m

any readers does the newspaper have?
Mathematics
1 answer:
SpyIntel [72]2 years ago
4 0

Answer:

<h3>1.6e8</h3>

Step-by-step explanation:

<h3>I don't know my answer is correct</h3>
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Help please ! order the side lengths GH , HI , IG from least to greatest
jok3333 [9.3K]

Answer:

IH < IG < HG

Step-by-step explanation:

To solve this equation remember that angle measurements correspond with sides. So, the largest angle will be opposite of the longest side and the smallest angle will be opposite of the shortest side.

First, you need to find m<I; do this by subtracting 52 and 45 from 180. This means that m<I=83, making it the largest angle. Therefore, the angles, in order of least to greatest, are <G, <H, <I. So, to find the final answer, find the sides opposite of each of the angles. This means the answer is IH < IG < HG.

7 0
3 years ago
The expression 50w+400 represents the amount of money Jenny has in her savings account after an unknown number of weeks. How muc
Sloan [31]

She originally had $400 in her bank account.

The 50w represents the amount she will put away each week.

3 0
3 years ago
Six years less than Tracey's age as an expression
likoan [24]

Answer:

T-6=X

Step-by-step explanation:

Tracey = T

X = Awnser

If we are subtracting six from Tracey's age, you would subtract six from T

since we don't know Tracey's age, it is represented by T.

Hope this Helps!

4 0
3 years ago
The Tire on franks bike moves 75 inches in one rotation. How many rotations will the tire have made after frank rides 50 feet
Sladkaya [172]
You have to convert 50 feet to inches, so you take 50 times 12 and get 600. Then, you take 600/75 to get the number of rotations. Your final answer shold be 8 rotations.
4 0
2 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
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