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3 years ago

5

What is the difference between the yearly wages of the highest paying job and lowest paying job, assuming Araceli will be paid f

or working 40 hours a week, 52 weeks a year

1 answer:

trasher [3.6K]3 years ago

4 0

Answer:

Is there a picture?? I need a picture

Step-by-step explanation:

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Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the same info

kow [346]

Graph is your answer look below for proof

have a good day!

3 0

3 years ago

nikitadnepr [17]

Answer:

y = (1/4)x - 3

Step-by-step explanation:

The slope-intercept form is y = mx + b. Here we are told that the line passes through (-8, -5) and that its slope is 1/4 (is that correct?).

Substituting -5 for y, -8 for x and 1/4 for m, we get an equation for the y-intercept, b:

-5 = (1/4)(-8) + b, or

-5 = -2 + b, so b = -3, and the desired equation is

y = (1/4)x - 3

3 0

2 years ago

Lisa family drove 830.76 miles to visit her grandpaerents.Lisa calculated that they used 30.1 gallons og gas .how many miles per

Irina-Kira [14]

830.76/30.1=27.6 miles

7 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago

In a store, a sample of 60 pens was selected from a box of 1,200 pens. Of these 60, 4 pens did not work. About how many pens cou

Lapatulllka [165]

Ok so if 1200 total pens and 60 were taken that's a ratio of 1200/60=20

out of 60pens 4 didn't work, again ratio is 4/60=1/15 so about 1/15 of the pens didn't work.

so we have 1200pens * 1/15broken ratio = 80 pens or we can say

20*4=80pens won't work from 20 groups of 60 and 4 out of 60 not working is 20*4=80 not working from total batch of 1200.

hope this helps you some! thank you!!!!!!!!!

3 0

3 years ago