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Aloiza [94]
3 years ago
10

Find the mid-point of (-2, 1, 4), (7, 3, -1)

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

2.5wdssfsfs

Step-by-step explanation:

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Please answer in a step by step explanation
Sphinxa [80]

Answer:

The answer is A

Step-by-step explanation:

2 less than three-fifths a number means that there is a number multiplied by 3/5 and you subtract two from it. 3/5n-2.

Less than or equal to is the one where the mouth is facing the right and there is a line under it

And then you have 41.

3 0
3 years ago
Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ

<u>Evaluate middle term</u>: 2tanθcotθ = 2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta} = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

<u>Apply trig identity:</u>  tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

<u>Apply trig identity:</u>  1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified


7 0
3 years ago
There are 600 performers in a dance recital. The ratio of men to women is 4:6. How many men performers were in the dance recital
posledela

Answer: 240 men

Step-by-step explanation:

From the question, we are informed that there were 600 performers in a dance recital and that the ratio of men to women is 4:6.

Fraction of men at the recital = 4/10

Fraction of women at the recital = 6/10

The number of men performers that were in the dance recital will be:

= 4/10 × 600

= 240 men

There were 240 men at the recital.

5 0
3 years ago
Plz answer I really need it
satela [25.4K]
It’s option C I believe.
8 0
3 years ago
Solve equation:<br><img src="https://tex.z-dn.net/?f=y%20%2B%20%20%5Cfrac%7B7%7D%7B8%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B8%7D%20"
Gala2k [10]

Answer: y = -1/2

Step-by-step explanation:

Subtract both sides by 7/8

y = 3/8 - 7/8

Then combine like terms

y = -4/8

Then simplify

y = -1/2

4 0
3 years ago
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