1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s344n2d4d5 [400]
2 years ago
12

24 x 0.17 lol help pls

Mathematics
1 answer:
Maurinko [17]2 years ago
6 0
24 x 0.17 equals 4.08 to be the answer
You might be interested in
The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in
Stolb23 [73]

Answer:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=34.5 represent the sample mean

\mu population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=300-1=299

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that t_{\alpha/2}=1.653

And the margin of error is given by:

ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75

±0.75 ounce

4 0
3 years ago
Read 2 more answers
Find the area of the shape.
Butoxors [25]
7 x 6 = 42 x 5 = 210 x 8 = 1,680 x 4 = [ 6,720 ]
4 0
3 years ago
Please help asap !!!
Firlakuza [10]
I believe that the answer is B. y=-7x+41
7 0
2 years ago
What is 2/3 divided by 1/6
yuradex [85]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Donna bought 4 bags of dog treats for $9.96. What is the cost per bag of dog treats?
sertanlavr [38]

Answer:

2.49 a bag

Step-by-step explanation:

7 0
2 years ago
Other questions:
  • A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica
    13·1 answer
  • Which equation has infinitely many real solutions?
    12·1 answer
  • Can anyone solve this for me?? I will give brainliest and 5 stars and thanks
    15·1 answer
  • Please Help i have a test the next day
    14·2 answers
  • The point (5,-2) is rotated 90° about the origin. Its image is<br> O (-2,5)<br> O (2,5)<br> O (-5,2)
    9·2 answers
  • Julia owns a clothing shop and went to a merchant's fair where she was able to buy 6 leather belts for $130. She then sells them
    8·1 answer
  • Danielle's car wash took in $185 to help raise money for the drama club. Danielle needed to spend $32 for car wash supplies. How
    15·1 answer
  • HELP GIVING 20 POINTS
    15·2 answers
  • • Low tide is 1 foot below the average water level.
    9·2 answers
  • Please Look Below In screenshot
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!