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2 years ago

PLEASE HELP WITH SERIES AND SEQUENCES!

Mathematics

1 answer:

Bingel [31]2 years ago

4 0

Answer:

145(145) I feel like it is but I can be wrong just try this but if not I don't know

Step-by-step explanation:

13+21=34+29=63+37=100+45=145

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237 devided by 8 times 564

Goshia [24]

237÷8×564 = 16708.5..

6 0

4 years ago

Arandom sample of n1 =12 students majoring in accounting in a college of business has a mean grade-point average of 2.70 (where

antiseptic1488 [7]

Answer:

We accept the null hypothesis that the mean gpa's are equal, with the 5 percent level of significance.

Step-by-step explanation:

We have these following hypothesis:

Null

Equal means

$\mu_{1} = \mu_{2}$

Alternative

Different means

$\mu_{1} \neq \mu_{2}$

Our test statistic is:

$\frac{\overline{Y_{1}} - \overline{Y_{2}}}{\sqrt{\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}}}}$

In which $\overline{Y_{1}}, \overline{Y_{2}}$ are the sample means, $N_{1}, N_{2}$ are the sample sizes and $s_{1}, s_{2}$ are the standard deviations of the sample.

In this problem, we have that:

$\overline{Y_{1}} = 2.7, s_{1} = 0.4, N_{1} = 12, \overline{Y_{2}} = 2.9, s_{2} = 0.3, N_{2} = 10$

$T = \frac{2.7 - 2.9}{\sqrt{\frac{0.4}^{2}{12} + \frac{0.3}^{2}{10}}} = -1.3383$

What to do with the null hypothesis?

We will reject the null hypothesis, that is, that the means are equal, with a significante level of $\alpha$ if

$|T| > t_{1-\frac{\alpha}{2},v}$

In which v is the number of degrees of freedom, given by

$v = \frac{(\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}})^{2}}{\frac{\frac{s_{1}^{2}}{N_{1}}}{N_{1}-1} + \frac{\frac{s_{2}^{2}}{N_{2}}}{N_{2} - 1}}$

Applying the formula in this problem, we have that:

$v = 20$

So, applying t at the t-table at a level of 0.975, with 20 degrees of freedom, we find that

$t = 2.086$

We have that

$|T| = 1.3383$

Which is lesser than t.

So we accept the null hypothesis that the mean gpa's are equal, with the 5 percent level of significance.

7 0

3 years ago

-4x+5(20/11)=-4<br><br> Please explain how to get x, thank u!

avanturin [10]

$-4x + 5 \left(\dfrac{20}{11}\right) =-4\\\\\implies \dfrac{100}{11} = -4+4x\\\\\implies 100 = -44+44x\\\\\implies 44x = 100 +44 = 144\\\\\implies x = \dfrac{144}{44} = \dfrac{36}{11}$