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3 years ago

If the sum of the squares of the legs of a right triangle are = to 144, the hypotenuse is...

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer: 12

Step-by-step explanation:

H^2=144

Square root of 144

H=12

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The drama club is printing t-shirts for its members. The printing company charges a certain amount for each shirt plus a setup f

Setler [38]

Answer: $7.

Step-by-step explanation:

It is given that the printing company charges a certain amount for each shirt plus a setup fee of $40.

Let x be the cost of each t-shirt.

There are 21 students in the drama club. So, total cost of 21 t-shirts is

$\text{Total cos}=40+21x$

It is given that the t-shirt order costs a total of $187.

$40+21x=187$

$21x=187-40$

$21x=147$

Divide both sides by 21.

$x=\dfrac{147}{21}$

$x=7$

Therefore, the cost of each t-shirt is $7.

4 0

3 years ago

On Monday, the ABC Company stock was at $12.80 per share. On Tuesday it gained $3.42, and then lost $9.70 on Wednesday. What is

solong [7]

Answer:

Step-by-step explanation:

12.80+3.42= 16.22

16.22-9.70= 6.52 that's your answer

6 0

3 years ago

Find the factors.

Allisa [31]

Answer:

Step-by-step explanation:

0.5334

0.06

75.1

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3 years ago

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

4 years ago

Identify a transformation of the function f(x) = x by observing the equation of the function g(x) = x − 16.

navik [9.2K]

The transformations are

(b) A vertical shift 16 units downward.
(d) A horizontal shift 16 units to the right

<h3>How to determine the transformation?</h3>

The functions are given as:

f(x) = x

g(x)= x - 16

When a function is shifted right, the transformation rule is:

(x, y) = (x - h, y)

This means that the transformation is (d) A horizontal shift 16 units to the right

Since the parent function is a base linear function.

The transformation can also be represented as:

(x, y) = (x, k - h)

This gives

g(x)= x - 16

This means that the transformation is (b) A vertical shift 16 units downward.

Hence, the transformations are (b) and (d)