I believe the answer is "true".
Answer:
- time = 1second
- maximum height = 16m
Step-by-step explanation:
Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation
f(t)=-16t²+32t... (1)
The pumpkin reaches its maximum height when the velocity is zero.
Velocity = {d(f(x)}/dt = -32t+32
Since v = 0m/s (at maximum height)
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
The pumpkin reaches its maximum height after 1second.
Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)
f(1) = -16(1)²+32(1)
f(1) = -16+32
f(1) = 16m
The maximum height of the pumpkin is 16m
Answer:
B. 8m ^ 18
Step-by-step explanation:
(2m ^6)^3 is the same as ;
(2 ^1 × m ^ 6) ^ 3.....multiply the powers 1 and 6 by 3
2 ^ (1×3) × m ^ (6×3).....this equals;
2 ^ 3 × m ^ 18
8m^18
hope this helps :)
Answer:
42 miles
Step-by-step explanation:
