If the expression ax(4x − 2y − 3) simplifies to 24x2− 12xy − 18, what must be the value of a?

Mathematics

2 answers:

almond37 [142]2 years ago

3 0

Answer:

a=6

Step-by-step explanation:

hope this helps

gregori [183]2 years ago

3 0

$\rm\red{\overbrace{\underbrace{\tt\color{orange}{\:\:\:\:\:\:\:\:Answer:\:\:\:\:\:\:\:\:\:}}}}$

$a = 6$

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Lower perfect square root of <br><br>18

sammy [17]

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7 0

3 years ago

Read 2 more answers

would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne

Leni [432]

The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
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Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-

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now factor by grouping
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(2x - 1)(x - 2) = 0
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The last example is solved in the same way.

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3 years ago

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

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$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .