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tia_tia [17]
2 years ago
11

If the expression ax(4x − 2y − 3) simplifies to 24x2− 12xy − 18, what must be the value of a?

Mathematics
2 answers:
almond37 [142]2 years ago
3 0

Answer:

a=6

Step-by-step explanation:

hope this helps

gregori [183]2 years ago
3 0

\rm\red{\overbrace{\underbrace{\tt\color{orange}{\:\:\:\:\:\:\:\:Answer:\:\:\:\:\:\:\:\:\:}}}}

a = 6

ChaEunWoo2009

#CarryOnLearning

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Lower perfect square root of <br><br>18​
sammy [17]
The lower square root would be 4.2
7 0
3 years ago
Read 2 more answers
would someone be able to explain to me how to solve these problems? I don't need the solutions, I just need an explanation. I ne
Leni [432]
The first 3  are examples of the difference of 2 squares so you use the identity 
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0 
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7  and 7.
Number 7 reduces to 3x^2 =12, x^2  = 4 so x = +/- 2
Number 8  take out GCf (d) to give 
d(d - 2)  = 0   so d = 0 ,  2
9 and 10 are more difficult to factor
you use the 'ac' method  Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end 
that is 2 * 2 =  4
Now we want  2 numbers  which when multiplied give + 4 and when added give - 5:-    -1 and -4  seem promising so we write the equation as:-

2x^2 - 4x - x + 2 = 0

now factor by grouping 
2x(x - 2) - 1(x - 2) = 0

(x - 2) is common so

(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0  and now you can find x.

The last example is solved in the same way.


8 0
3 years ago
Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G
Kaylis [27]

\Rightarrow

Suppose first that H\subset G is a normal subgroup. Then by definition we must have for all a\in H, xax^{-1} \in H for every x\in G. Let a\in G and choose (ab)\in aH (b\in H). By hypothesis we have aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H, i.e. aba^{-1}=c for some c\in H, thus ab=ca \in Ha. So we have aH\subset Ha. You can prove Ha\subset aH in the same way.

\Leftarrow

Suppose aH=Ha for all a\in G. Let h\in H, we have to prove  aha^{-1} \in H for every a\in G. So, let a\in G. We have that ha^{-1} =a^{-1}h' for some h'\in H (by the hypothesis). hence we have aha^{-1}=h' \in H. Because a was chosen arbitrarily  we have the desired .

 

5 0
3 years ago
ABCD FECG
MariettaO [177]

Answer:

x=12

Step-by-step explanation:

7 0
2 years ago
3x-2x+8=12; x=4 <br>Determine if the value of x is a solution to the equation<br>​
VARVARA [1.3K]

Step-by-step explanation:

3x - 2x + 8 = 12; x=4

Now, Evaluate the value of x

3(4) - 2(4) + 8 = 12

12 - 8 + 8 = 12

12 + 0 = 12

12 = 12

4 0
2 years ago
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