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Gnom [1K]
3 years ago
6

Given that f(x)=x-5 g(x)=5x and h(x)=-f(x+1)-3g(x-1), then what is the value of h(3)?

Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

Step-by-step explanation:

f(x) = x - 5 and g(x) = 5x

- f(x + 1) = - ( x + 1 - 5 ) = 4 - x

- 3g(x - 1 ) = - 3 [ 5 (x - 1)] = 15 - 15x

<em>h(x)</em> = 4 - x + 15 - 15x = <em>19 - 16x</em>

<em>h(3)</em> = 19 - 16(3) = <em>- 29</em>

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Next, divide both sides of the equation by 4. You should end up with m=-8. (A negative divided by a positive equals a negative)

Hope this helps! Have a great day ;)
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ankoles [38]

Answer:

He had hiked 3/12 of a mile so the answer is 8/12 of a mile

Step-by-step explanation:

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3 years ago
If u+v+w=0, show that u x v = v x w = w x u.
Flauer [41]
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(\mathbf u+\mathbf v+\mathbf w)\times\left\{\begin{matrix}\mathbf u\\\mathbf v\\\mathbf w\end{matrix}\right\}=\mathbf0\times\left\{\begin{matrix}\mathbf u\\\mathbf v\\\mathbf w\end{matrix}\right\}
\implies\begin{cases}\mathbf u\times\mathbf u+\mathbf u\times\mathbf v+\mathbf u\times\mathbf w=\mathbf0\\\mathbf v\times\mathbf u+\mathbf v\times\mathbf v+\mathbf v\times\mathbf w=\mathbf0\\\mathbf w\times\mathbf u+\mathbf w\times\mathbf v+\mathbf w\times\mathbf w=\mathbf0\end{cases}
\implies\begin{cases}\mathbf u\times\mathbf v+\mathbf u\times\mathbf w=\mathbf0\\\mathbf v\times\mathbf u+\mathbf v\times\mathbf w=\mathbf0\\\mathbf w\times\mathbf u+\mathbf w\times\mathbf v=\mathbf0\end{cases}

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4 0
4 years ago
Martens got a small aquarium forgot her birthday. The aquarium is a right rectangular prism 18.5cm long by 15cm wide. Martens pu
sp2606 [1]

Answer:

Depth of Martens aquarium water = 14 cm.

Step-by-step explanation:

Given:

An aquarium,which is a right rectangular prism.

Length of the aquarium, l = 18.5 cm

Width of the aquarium, b = 15 cm

Volume of the aquarium, V = 3885 cm cubes

We have to find the depth of the aquarium.

Let the depth be h cm.

Note:

Volume of the rectangular prism,V=lbh.

⇒ V = l\times b\times h

⇒ h=\frac{V}{l\times b}

⇒ Plugging the values.

⇒ h=\frac{3885\ cm^3}{18.5\ cm\times 15\ cm}

⇒ h=14 cm

So,

The depth of the aquarium water is 14 cm.

4 0
4 years ago
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