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2 years ago

A 2020 Toyota Prius c hybrid vehicle gets about 48 miles per gallon while driving

1 answer:

6 0

The distance that can be traveled on the highway after the fuel light comes on and before the car runs out of gasoline is 96 miles.

Given that a 2020 Toyota Prius hybrid vehicle gets about 48 miles per gallon while driving on the highway, and the tank holds 11.3 gallons of fuel, and typically the low fuel warning light comes on when approximately two gallons of fuel remain in the tank, to find the distance that can be traveled on the highway after the fuel light comes on and before the car runs out of gasoline the following calculation should be performed:

1 = 48
2 = 48 x 2
2 = 96

Therefore, the distance that can be traveled on the highway after the fuel light comes on and before the car runs out of gasoline is 96 miles.

Learn more in brainly.com/question/18592149

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A swimming pool has to be drained for maintenance. The pool is shaped like a cylinder with a diameter of 5 m and a depth of 1.4

Korolek [52]

Answer:

8 hours

Step-by-step explanation:

basic equation

Q (flow rate) = V (volume)/ t (time)

so to find the time we just rearrange the equation and become

t = V/Q

V of cylinder

V = πr²T

and r (radius) = ½ diameter

V = 3.14 x 5² x 1.4

V = 109.9 m³

if the Q is 13 m³/hour then

t = 109.9/13 = 8.453 hours

round to nearest hour = 8 hours

6 0

2 years ago

The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately

Vanyuwa [196]

Answer:

a. S = {A,B,AB,O}

b. P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c. 0.45 = 45% probability that the person chosen at random has either type A or type AB blood

Step-by-step explanation:

a List the sample space for this experiment.

All possible blood types(A, B, AB or O). So

S = {A,B,AB,O}

b Make use of the information given above to assign probabilities to each of the simple events.

The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately .41, .10, .04, and .45, respectively.

P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c What is the probability that the person chosen at random has either type A or type AB blood

P(A) + P(AB) = 0.41 + 0.04 = 0.45

0.45 = 45% probability that the person chosen at random has either type A or type AB blood

6 0

2 years ago

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$