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Maslowich
2 years ago
11

If an angle is acute, then the measure of its complement must be greater than the measure of its

Mathematics
1 answer:
salantis [7]2 years ago
5 0

Answer: acute angles are higher that 0° and smaller than 90°

Step-by-step explanation: obtuse are between 90° and 180°

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Identify the property of (-12)+12=0
photoshop1234 [79]

Answer:

the anser is 0

this is an additive inverse property.

Step-by-step explanation:

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1 year ago
What is the volume of a tank that can hold 18 754 Kg of methanol whose density is 0.788g/cm3
Alenkasestr [34]
Density = Mass / Volume
(0.788) = (18.754) / V
0.788V = 18.754
V = (18.754) / (0.788)
V = 23.799
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3 years ago
Two friends share 7 cookies equally. How many cookies does each friend get?
shusha [124]
7÷2=3.5 each of them get 3.5 cookies
5 0
3 years ago
Read 2 more answers
A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0
3 years ago
Molly wants to buy a dress that costs $20. She has a coupon for 40% off, and there is a 10% sales tax. How much will she pay alt
Svet_ta [14]

Answer:

8

Step-by-step explanation:

multiply 40 x 20 which =80

then put a point after the 8 then add a 0.

Your final answer should be 40% of $20 is $8.00

7 0
3 years ago
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