we know that
In a right triangle we have
two legs and one hypotenuse
Let
a,b -----> the legs of the right triangle
c-----> the hypotenuse of the right triangle (the greater side)
Applying the Pythagoras Theorem
therefore
<u>the answer is</u>
The length of the hypotenuse squared is the length of one leg squared plus the length of another leg squared
In triangle b. we know that tan(x) = Opposite side to x angle / Adjacent side to angle x.
By substituting in above formula,
tan(x) = 12/5 = 2.4
x = tan^-1(2.4) = 68 degrees.
And in triangle a. i am not clear with the angle. Is it 51 or any other?
Answer:
![\sqrt[n]{x}=x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Step-by-step explanation:
The index of a radical is the denominator of a fractional exponent, and vice versa. If you think about the rules of exponents, you know this must be so.
For example, consider the cube root:
![\sqrt[3]{x}\cdot \sqrt[3]{x}\cdot \sqrt[3]{x}=(\sqrt[3]{x})^3=x\\\\(x^{\frac{1}{3}})^3=x^{\frac{3}{3}}=x^1=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bx%7D%3D%28%5Csqrt%5B3%5D%7Bx%7D%29%5E3%3Dx%5C%5C%5C%5C%28x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3Dx%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3Dx%5E1%3Dx)
That is ...
![\sqrt[3]{x}=x^{\frac{1}{3}} \quad\text{radical index = fraction denominator}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cquad%5Ctext%7Bradical%20index%20%3D%20fraction%20denominator%7D)
16/34, ratio is other words of fraction, also means 16out of 34
The Answer is 2/3
Steps: 1/4(1-(2/3^2+1/3)
