c
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer: 6 u^2 + 4u + 6 = 0 where u = (x-5)^2
Discussion; I think the problem statement should actually be to rewrite <u>this</u> equation:
6 (x-5)^4 + 4 (x-5)^2 + 6 -= 0.
Note the power of "x-5" is 4 in the first term and is 2 in the second term. That is, the power of x-5 in the first terms is double, or the square, of the (x-5) power occurring in the second term. This suggest the substitution u = (x-5)^2. Then the equation can be rewritten as
6 u^2 + 4u + 6 = 0
which is a quadratic in "u".
Regards, MrB
The answer to your question is x=2. what you want to do is find both the x values for your quadratic equation and then add them and divide by 2.
Answer: You say “You're on thin ice”.
AJ has the orthogonal from the sides of a & b thank you