All categories

2 years ago

-2.35 - (-1.27) as a fraction in simplest form

Mathematics

1 answer:

Grace [21]2 years ago

3 0

The answer is -1 2/25

You might be interested in

What happens to the slope when a line with positive slope gets close to vertical

Nuetrik [128]

The value of the slope increases and becomes closer to infinity

4 0

3 years ago

Fix the mistake in my screenshot

mixas84 [53]

Answer:

Step-by-step explanation:

x $\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx$ XE[_4.2,2.2]

8 0

2 years ago

F(x) = x^2 - 4, X is greater/less than 0<br><br> (a) Find the inverse function of f.<br> F^-1(x) =

Natali5045456 [20]

Step-by-step explanation:

f(x) = x² - 4

y = x²-4

x = y²-4

x + 4 = y²

$y = \sqrt{x + 4}$

7 0

2 years ago

Use the Distributive Property to expand 4(x+3)

Serga [27]

Answer:

4x+12

Step-by-step explanation:

4(x+3)=4x+12.

You use the distributive property by multiplying both numbers in the parentheses by 4

6 0

2 years ago

Read 2 more answers

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago

-2.35 - (-1.27) as a fraction in simplest form​

-2.35 - (-1.27) as a fraction in simplest form