3 years ago

Is it possible to construct a triangle with side lengths of 6 cm, 11 cm, and 13 cm? Why or why not?

Mathematics

2 answers:

Airida [17]3 years ago

6 0

Answer:

Answer is D took the test

Step-by-step explanation:

AlexFokin [52]3 years ago

3 0

<span>C. No, because 6 + 11 = 13. </span>

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Step-by-step explanation:

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3 years ago

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yawa3891 [41]

Answer:

$15x {y}^{7} z$

Step-by-step explanation:

<h3>Factorize the Expressions</h3>

$15x {y}^{2} z = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

$30 {x}^{2} {y}^{7} z = 2 \times 3 \times 5 \times x \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Factor out the Common Factors</h3>

$gcf = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Multiply the Common Factors</h3>

$3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z = 15x {y}^{7} z$

The Factored expressions are

$15x {y}^{7} z$

And

$15x {y}^{7} (2x)$

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4 years ago

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mr_godi [17]

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3 years ago

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