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notka56 [123]
3 years ago
5

Marco wants to buy a new smartphone that costs $495. He has already saved $75. Write and solve an inequality to find the least a

mount of money,
m, that Marco still needs to save before he can buy the smartphone. Enter your answer in the box
Marco needs to save at least $
Mathematics
2 answers:
san4es73 [151]3 years ago
6 0

Here's a screenshot of the answer below:

Mamont248 [21]3 years ago
4 0

Answer:

495-75=420 so

(−10,7)∪(7,11)(−1,2)∪(−4,0)[−1,9)∪(2,10]

Step-by-step explanation:

420 is that Marco still needs to save before he can buy the smartphone.

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Evaluate the expression when n= -2<br> 5n+30
sammy [17]

Answer:

20

Step-by-step explanation:

5(-2)+30 = (-10)+30 = 20

6 0
3 years ago
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List all the pairs of integers with a product of 36. then find the pair whose sum is 20
RoseWind [281]
This is an excellent practice for the solution of quadratic equations.

1*36=36  => (1,36)
2*18=36  => (2,18)
3*12=36  => (3,12)
4*9=36   => (4,9)
6*6=36   => (6,6)
9*4=36   => (9,4)
12*3=36  => (12,3)
18*2=36  => (18,2)
36*1=36  => (36,1)

We can see that the sum decreases until the two factors are close (or equal) and then increases again.

The pair of integers with a sum of 20 is therefore (2,18) or (18,2).
4 0
4 years ago
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An amount of $350,000 is borrowed for a period of 30 years at an interest rate of 5.5%. The amortization schedule for this
Annette [7]
350,000 . 250,00 . 1,987.26
8 0
3 years ago
X and y are both bigger than 30. x and y have HCF 21 and LCM 1617. Find x and y.
Sunny_sXe [5.5K]

The values of x and y are 99 and 343

<h3>The HCF</h3>

The HCF of numbers is the highest common factors of the numbers

<h3>The LCM</h3>

The LCM of numbers is the lowest common multiple of the numbers

The HCF and the LCM are given as:

HCF = 21

LCM = 1617

Multiply the HCF and the LCM

HCF \times LCM = 21 \times 1617

HCF \times LCM = 33957

The product of the numbers x and y equals the product of the HCF and the LCM.

So, we have:

x \times y = 33957

<h3>Prime Factors</h3>

Express 33957 as a prime factor

x \times y = 3^2 \times 7^3 \times 11

Rewrite the equation as

x \times y = 99 \times 7^3

x \times y = 99 \times 343

By comparison:

x = 99

y= 343

Hence, the values of x and y are 99 and 343

Read more about HCF and LCM at:

brainly.com/question/420337

6 0
3 years ago
Yo i need help with 1,000,000 + - 3,000,000
Arada [10]

Answer: -2,000,000

Step-by-step explanation:

Think of it as -3,000,000 + 1,000,000

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