All categories

3 years ago

Solve pls brainliest

Mathematics

2 answers:

NikAS [45]3 years ago

7 0

The least common denominator is 12

Umnica [9.8K]3 years ago

5 0

Answer:

LCD = 12

Equivalent Fractions with the LCD

1/6 = 2/12

9/4 = 27/12

Step-by-step explanation:

hope this helps have a good day:)

You might be interested in

Kaleb makes an investment at 5.2 percent simple interest. At the end of 1 year, the total value of the investment is $2419.60. H

Dafna11 [192]

The future amount of the current deposit given that the interest is simple and yearly is computed through the equation,
F = P x (1 + in)
where P is the principal amount, F is the future amount, i is the interest (in decimal form) and n is the number of years.

In this certain problem, we substitute the known values to the equation and solve for P,
2419.60 = P x (1 + (0.052)(1))
P = 2300
Thus, the initial investment was worth $2,300.

3 0

3 years ago

Find two positive numbers whose product is 36 and whose sum is a minimum.

alukav5142 [94]

Let one of the numbers be x. The other number cab then be represented as 36-x (x+36-x = 36).
The product can then be represented as y = x(36-x) or y=36x-x2

The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.
In our case, the axis of symmetry is -36/-2, so x=18.

If one number is 18 and the 2 numbers add to 36, the other number is 18 as well.
So the 2 numbers are 18 and 18 and the maximum product is 324,

8 0

3 years ago

Evaluate each expression. 1. 3x5+2x8+2

kirza4 [7]

Answer:

1.23

2.60

3.45

4.37.524 (Im not incredibly posotive ab this one)

5.28

Step-by-step explanation:

4 0

3 years ago

A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life

alisha [4.7K]

Answer:

The null hypothesis is $H_0: \mu \leq 10$

The alternative hypothesis is $H_1: \mu > 10$

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

$H_0: \mu \leq 10$

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

$H_1: \mu > 10$

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that $\mu = 10$

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that $n = 45, X = 10.5, s = 1.8$

Then

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}$

$t = 1.86$

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0

3 years ago

Simplify: (3) + (-4)

nikitadnepr [17]

Answer:

it should -1 because you have to evaluate the number

3 0

3 years ago