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3 years ago

Solve pls brainliest

Mathematics

2 answers:

NikAS [45]3 years ago

7 0

The least common denominator is 12

Umnica [9.8K]3 years ago

5 0

Answer:

LCD = 12

Equivalent Fractions with the LCD

1/6 = 2/12

9/4 = 27/12

Step-by-step explanation:

hope this helps have a good day:)

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THIS IS URGENT, IM ABOUT TO START CRYING!!!

tresset_1 [31]

PART A:

Finding the slope of the function f(x)

Choose any two pairs of coordinate from the table; (-1, -15) and (0, -10)

Let (-1, -15) be (x₁, y₁) and (0, -10) be (x₂, y₂)

Slope =

Slope of f(x) = 5

The function g(x) is given in the straight line equation form

Where, is the slope and is the y-intercept

Slope of g(x) = 2

-----------------------------------------------------------------------------------------------------------

g(x) = 2x + 8

Where, the slope (m) = 2 and the y-intercept (c) = 8

The y-intercept of g(x) is 8

for f(x), we can read the y-intercept when x = 0.

From the table, when x = 0, y = -10

The y-intercept of f(x) is -10

Function g(x) has higher y-intercept

3 0

3 years ago

Two similar triangles are shown

slavikrds [6]

Answer: D

Step-by-step explanation:

Because they are similar all u have to do is add the sides

7 0

3 years ago

Read 2 more answers

I need help plssssss

Black_prince [1.1K]

Substitute the values given.
-2-3(2) then solve
Your answer should be -8

5 0

2 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$