Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Answer :
Two Hours
Step By Step :
20-4=16
16/8=2
Answer:
idk a or c
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Trinomial can not be factored
Step-by-step explanation Equation at the end of step 2 : 4x 2 - 2x - 1 = 0 Step 3 : Parabola, Finding the Vertex : 3.1 Find the Vertex of y = 4x 2-2x-1 Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum)
