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IgorC [24]
3 years ago
12

When graphing an inequality that uses < or >, a person would use a closed (filled-in) circle or an open (not filled-in) ci

rcle
closed


open
Mathematics
2 answers:
ANTONII [103]3 years ago
8 0

Answer:

Open

Step-by-step explanation:

Closed =  \geq or \leq

Open = > or <

Alinara [238K]3 years ago
5 0

Answer:

Open

Step-by-step explanation:

Since the equality is either greater than or less than, that means the number cannot be the number we start plotting the point on. Therefore, the circle has to be open.

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Find and simplify an expression for the area of two rows of b squares with side lengths of b centimeters. Please help!
Ronch [10]

Answer:

The complete area of the given figure is (2 b^3) cm^2

Step-by-step explanation:

Total number of rows = 2

Squares in each row = b

So, the total number of  squares in 2 rows = 2 x ( Squares in 1 row ) = 2 x  b

Also, side length of 1 square = b cm

As we know, AREA OF SQUARE  = SIDE x SIDE

So here, area of 1 square  = Side x side  = b cm  x b cm = (b^2) cm^2

⇒ The area of total (2b) squares  = 2 b x ( Area of  1 square)

= 2 b \times (b^2)  = 2 b^3

Hence, the complete area of the given figure is (2 b^3) cm^2

6 0
3 years ago
53% of 80<br> ? What is the percentage?
quester [9]

Answer:

42.4

Hope that this helps!

5 0
3 years ago
Read 2 more answers
PLEASE HELP
jenyasd209 [6]

Answer:

Step-by-step explanation:

F(x) results in a parabola with vertex (0,0) wich mean there is only one x-int at that point. g(x) has been shifted the grapgh of f(x) to the right by to units and down by three unites. Now our vertex lies in the point (2,-3) and since the graph was move dow i=of the x-axis we now have two different x-intercepts.

7 0
3 years ago
A baseball is dropped from a glider 500 feet above the ground. The height (in feet) above the ground is modeled by the function
Sophie [7]

A) 436 ft

B) t = 5 sec

C) 5.60 s

Step-by-step explanation:

A)

The height of the ball at time t is given by the equation

h(t)=-16t^2+500

where

-16 ft/s^2 is the acceleration of the ball (acceleration of gravity, downward)

+500 is the initial height of the ball, at time t = 0

Here we want to find the height of the ball after 2 seconds, so at a time of

t = 2 s

Substituting into the equation, we find:

h(2)=-16\cdot 2^2+500=436 ft

B)

Here we want to find the time it takes for the ball to fall to a height of 100 feet above the ground, so the time t at which

h(t) = 100 ft

As stated in the text of the question, the height of the ball at time t is given by

h(t)=-16t^2+500

Since

h(t) = 100, we have

100=-16t^2+500

And solving for t we find:

16t^2=400\\t^2=25\\t=\pm 5

So, the correct solution is the positive one:

t = 5 sec

C)

The ball reaches the ground when the height of the ball has became zero:

h(t) = 0

The height of the ball at time t is given by

h(t)=-16t^2+500

And substituting

h(t) = 0

We get

0=-16t^2+500

And solving the equation for t, we find the time t at which the ball reaches the ground:

16t^2=500\\t^2=31.25\\t=\pm 5.6 s

So, the correct solution is the positive one:

t = 5.60 s

3 0
4 years ago
What are the next two terms in the sequence 22, 15, 8, __, __? 1, -7 2, -4 2, -6 1, -6
Step2247 [10]

Step-by-step explanation:

The sequence is an AP with common difference -7.

Therefore the next 2 terms are 1 and -6.

5 0
3 years ago
Read 2 more answers
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