Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
Answer: C . 147π / 4 mi²
Concept:
The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.
A = (θ / 360) πr²
θ = angle of the sector
π = constant
r = radius
Solve:
<u>Given variable</u>
θ = 270°
r = 7 mi
<u>Given formula</u>
A = (θ / 360) πr²
<u>Substitute values into the formula</u>
A = (270 / 360) π (7)²
<u>Simplify exponents</u>
A = (270 / 360) π 49
<u>Simplify by multiplication</u>
A = (147 / 4) π
A = 147π / 4
Hope this helps!! :)
Please let me know if you have any questions
Answer:
8.75%
Step-by-step explanation:
If she pays $135 eight times then she pays a total of 135 x 8 = $1080.
She had a down payment of $225, so that added on becomes $1305.
1305/1200 is 1.0875, which is an increase of 0.0875 over the original.
0.0875 x 100 = 8.75% increase.
Answer: is 1.41421 hope this helps :)
