I believe it is Since the square root of 9 = 3 and the square root of 16 = 4 it is known the the square root of 12 is in between 3 and 4. Really hope this helps!
Answer:
Step-by-step explanation:
cos (2α)*sin (α-β)-cos(β-α)*sin(2α)
cos (β-α)=cos {-(α-β)}=cos (α-β)
[cos (-x)=cos x]
sin(α-β)*cos (2α)-cos (α-β)*sin (2α)=sin (α-β-2α)=sin (-α-β)
=sin {-(α+β)}
=-sin (α+β)
You need to add a -1
We can find this by setting up the equation like so
x + (-6) + 12 + 15 / 4 = 5
x + 21 = 20
x = 20 -21
x = -1
Now if we insert -1 where x is located in the equation, you will get a means of 5