3 A farmer has 580 square bales of hay in his shed with total mass 9850 kg.

Mathematics

1 answer:

rusak2 [61]2 years ago

4 0

Answer:

a) 580 - 16n

b) 9850 - 271.72n

Step-by-step explanation:

a) starting number of bales = 580

each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day

After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is

original amount - amount lost = 580 - 16n

First, we can calculate how much a bale weighs.

average = sum/count = 9850 kg / 580 ≈ 17 kg

Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be

starting - amount lost = 9850 - 271.72n

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$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
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\end{cases}
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