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STALIN [3.7K]
2 years ago
9

A circuit has a current of (8 + 7i) amps, and another circuit has a

Mathematics
2 answers:
Schach [20]2 years ago
8 0

Answer:

Answer: <u> </u><u> </u><u>3</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u>i</u><u> </u>

Step-by-step explanation:

= { \rm{(8 + 7i) - (5 - 3i)}} \\  \\  = { \rm{(8 - 5) + (7 + 3)i}} \\  \\ { =  \rm{3 + 10i}}

Ann [662]2 years ago
3 0

(8 + 7i) - (5 - 3i)

\longrightarrow \: (8 + 7i - 5 + 3i)

\longrightarrow \: (3 + 10i)

3+10i is the difference between the current of the two circuits

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3 years ago
Find the missing side length and round it to the nearest tenth please :)
Alchen [17]

Answer:

171

Step-by-step explanation:

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The product of 6 and 2 added to the quotient of 9 and 3
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8 0
2 years ago
Read 2 more answers
A baseball team's total wins and losses for one season is 162. The number of wins is 6 less than 2 times the number of losses. W
aivan3 [116]

Answer:

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Step-by-step explanation:

Let the total wins be x

Let the total loss be y

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x + y = 162 ....... 1

If the number of wins is 6 less than 2 times the number of losses, this is expressed as;

2 times the number of losses = 2y

6 less than 2 times the number of losses = 2y - 6

Now, If the number of wins is 6 less than 2 times the number of losses this is expressed as;

x = 2y - 6 .... 2

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x + y = 162 and x = 2y - 6

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2 years ago
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It would be the second answer.
8 0
3 years ago
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