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2 years ago

9

A circuit has a current of (8 + 7i) amps, and another circuit has a

2 answers:

Schach [20]2 years ago

8 0

Answer:

Answer: <u> </u><u> </u><u>3</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u>i</u><u> </u>

Step-by-step explanation:

$= { \rm{(8 + 7i) - (5 - 3i)}} \\ \\ = { \rm{(8 - 5) + (7 + 3)i}} \\ \\ { = \rm{3 + 10i}}$

Ann [662]2 years ago

3 0

$(8 + 7i) - (5 - 3i)$

$\longrightarrow \: (8 + 7i - 5 + 3i)$

$\longrightarrow \: (3 + 10i)$

3+10i is the difference between the current of the two circuits

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